Calculus extrema

Question

Consider

h(s) = 1/(s-2)

on [0, 1]

a) what is its maximum value?

b) what is it’s minimum value?

Answer 1

Hi Kalea,

There's a straightforward procedure for finding the maximum and minimum values of a continuous function on a closed interval.

First find any critical points of the function in the interval. These are places where h'(s) = 0 or is undefined.

Evaluate the function at each critical point in the interval and at the 2 endpoints of the interval. The largest of these values is the maximum value, and the smallest is the minimum.