Michael H. answered 11/13/19
High School Math, Physics, Computer Science & SAT/GRE/AP/PRAXIS Prep
Note that (a) is a special case of (b), and that (b) is a special case of (c). We will solve (c) first, then solve(b), the solve (a).
c) The total cost T is simply T = 2*A*x + 2*B*y
The Area G of the plot is G = x*y, and we wish to maximize A.
Solve for y as follows:
2*A*x + 2*B*y = T
2*B*y = T - 2*A*x
y = ( T - 2*A*x ) / (2*B)
Write G as a function of x alone:
G(x) = x*y = x*( T - 2*A*x ) / (2*B)
dG/dx = 1 * ( T - 2*A*x ) / (2*B) + x*( - 2*A ) / (2*B) = ( T - 2*A*x - 2*A*x ) / (2*B) = (T - 4*A*x) / (2*B)
= 0 when
T - 4*A*x = 0
x = T / (4*A)
y = (T - 2*A*x ) / (2*B) = ( T - 2*A*T/(4*A) ) / (2*B) = (T - T/2 ) / (2*B) = T / (4*B)
x,y define a maximum G because the second derivative of G is negative:
d2G/dx2 = -4A / 2B < 0 as long as A and B > 0.
b) Here, A=5, B=3.
x = T / (4*A) = T / (4*5) = T / 20
y = T / (4*B) = T / (4*3) = T / 12
T = 2Ax + 2By = 2(5)(T / 20) + 2(3)(T / 12) = T / 2 + T / 2
Cost to build side x: T / 2
Cost to build side y: T/ 2
a) Here, A=5, B=3, and T=9000
x = T/20 = 9000 / 20 = 450
y = T/12 = 9000 / 12 = 750
T = 2Ax + 2By = 2(5)(450) + 2(3)(750) = 4500 + 4500
Cost to build side x: $4500
Cost to build side y: $4500