Mark M. answered 11/12/19
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f'(x) = 12x2
f(x) = ∫f'(x)dx = ∫(12x2)dx = 4x3 + C
Since f(0) = 8, 4(0)3 + C = -8. So, C = -8.
f(x) = 4x3 - 8