Patrick B. answered 11/04/19
Math and computer tutor/teacher
y = x(1-x) / (x-1)(x-2)
= -x/(x-2) = -x(x-2)^(-1)
domain is all reals except 2, R - {2}, (-infinity, 2) u (2, infinity)
x-intercept(0,0)
y-intercept(0,0)
vertical asym. x=2
horizontal asym. -1
Per quotient rule
y' = {(x-2)(-1) - (-x)} / (x-2)^2 =
2/(x-2)^2
= 2(x-2)^(-2)
Per product rule:
(-x)(-1)(x-2)^(-2) + -(x-2)^(-1)
= (x-2)^(-2) { x - (x-2)} = 2/(x-2)^2
derivative is zero NOWHERE!!!
therefore the function is increasing EVERYWHERE in it's domain,
because y'>0
y'' = (-4)(x-2)^(-3) which is negative for x<2 and positive for x>2 so no flex points.
for x<2, it is concave up; for x>2 it is concave down