What is the antiderivative of f(x) = 5x^4– 4x^3 + 2 where f(1) = 6?

Answer 1

Hi

The anti-derivative of the function

f(x) = 5x^4– 4x^3 + 2 is:

F(x)=x^5 -x^4+2x+constant

according to the rule integrate(x^n)=(1/n+1)x^(n+1)

F(1)=6 2+constant=6 so constant = 4

finally: F(x)=x^5 -x^4+2x+6

Good Luck