Mark M. answered 10/26/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let x = length of a side of the base and y = height
Then, x2y = 10. So, y = 10 / x2.
C = cost = 0.20x2 + 0.25(x2 + 4xy) = 0.45x2 + x(10 / x2) = 0.45x2 + 10x-1
dC / dx = 0.90x - 10 / x2 = [0.90x3 - 10] / x2
dC/dx = 0 when 0.90x3 = 10
x3 = 11.11111
Minimum cost when x = 2.23 ft and y = 2.01 ft