Ethem S. answered 10/24/19
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s = 0.33t^2 + 2.27t + 3.96 = 9.8, solve for t
0.33t^2 + 2.27t - 5.84 = 0
t = (-b +- sqrt(b^2 - 4ac)) / 2a
b^2 - 4ac = 2.27^2 + 4*0.33*5.84 = 12.86
t = (-0.33 +- sqrt(12.86) ) / 2*0.33 = ( -0.33 +- 3.59 ) / 0.66
We need to positive solution
t ~ 5 years from 2000 so 2005