
Mark H. answered 10/22/19
Tutoring in Math and Science at all levels
f(x) =xe^-(x^2 -x)/2
I assume you meant:
f(x) =xe-(x^2 -x)/2
First, find the slope by taking the 1st derivative. For f'(x), I get:
f'(x) = e-(x^2 -x)/2 + x*(-e-(x^2 -x)/2 * -(2x - 1)/2
= (1+x-4 +1/2)* e-(x^2 -x)/2
= (x - 2.5)*e-(x^2 -x)/2
Find f'(1), which the the slope of L(x). Then you can generate the equation for L(x) using the slope and the given point ( (x,y) where x = 1, and y = f(1) )