Let h(x)=1/(x-2)^3 . Find two functions f and g such that h(x)= (f(g(x))

Question

I need the answer before 7pm

Answer 1

There are LOTS of possibilities.

One easy one would be f(x) = 1/x³ and g(x) = x - 2

Another could be f(x) = 1/x and g(x) = (x - 2)³

Or you could even make it as dumb as f(x) = x and g(x) = 1/(x-2)³