if f(x)=[√x][g(x)], where g(4)=2 and g'(4)=3, find f'(4)

Answer 1

f(x) = √xg(x)

By the Product Rule, f'(x) = [1 / (2√x)]g(x) + √xg'(x)

So, f'(4) = [1/4](2) + (2)(3) = 6.5