Javascript Coding Help

Question

Create an array that stores the names of five dogs.

Using a loop, evaluate an array index for even numbers. If the value is even, then output "dog name is a good dog", and if it is an odd number, "dog name is a bad dog."

var mydogs= ["Fifi","Fido","Felix","Floppy","Flipper"];

for (i=0;i < mydogs.length;i++)

{

   if ( _____  ){ console.log(mydogs[i] + " is a good dog");}

Answer 1

Hi Chris,

I hope its not too late.

In order to find whether a number is even or odd, you use the modulus (%) operator. e.g if i mod 2 gives zero, it means i is even. The mod x % y is used to Divides the left hand operand by the right hand operand and returns remainder. Remainder of even number divided by 2 will always return 0.

var mydogs= ["Fifi","Fido","Felix","Floppy","Flipper"];

for (i=0;i < mydogs.length;i++)

{

   if ( i % 2 == 0  ) {

  console.log(mydogs[i] + " is a good dog");

} else {

console.log(mydogs[i] + " is a bad dog");

}

}

Answer 2

In your for loop you have already gotten access to each individual dog's name. What you can probably do is find the length of your dog's name and see if that number is even or odd. Here you can probably use the modulus operator in javascript to help you with your check. That should allow you to attach good or bad dog to your output.