Given the equationy= ln(x^2+ 9)

Question

a) Find the differential dy.

b) Evaluated y if x= 4and dx= 0.1

Answer 1

ETHAN,

dy/dx = f'(x), so dy = f'(x) *dx

In this case: dy/dx = 1/(x^2 +9) * 2x --> dy = [2x/(x^2 + 9) ]*dx

dy =[ 8/(16+9)]*0.1 = 8/25 *0.1 = 0.032