Arthur D. answered 10/16/19
Mathematics Tutor With a Master's Degree In Mathematics
1.) Allen takes x minutes to do the job
Jack takes x-20 minutes to do the job
1/(x-20)(10)+(1/x)(15)=1 (job done)
multiply both sides by x(x-20) to get...
10x+15(x-20)=x(x-20)
10x+15x-300=x^2-20x
x^2-20x-25x+300=0
x^2-45x+300=0
use the quadratic equation
{45±√(2025-1200)}/2
{45±√825}/2
(45±28.7228)/2
73.7228/2
36.86 minutes
36.7 minutes for Allen
36.86-20=16.7 minutes for Jack
check: (1/16.7)(10)+(1/36.7)(15)=1
0.5988+0.4087=1.0075 (this exceeds 1 because you rounded up)
2.) x=# of cups
y=cost of one cup
xy=$48
(x-2)(y+3)=70
xy=48 implies x=48/y
substitute
([48/y]-2)(y+3)=70
multiply both sides by y to get...
(48-2y)(y+3)=70y
48y-2y^2+144-6y=70y
combine similar terms and get all terms on one side
2y^2+28y-144=0
y^2+14y-72=0
factor or use the quadratic equation
(y+18)(y-4)=0
y=-18 makes no sense
y=4
$4 per cup for the cost and 12 cups were bought (48/4)
check: keep 2 cups and sell 10 cups for $3 more than $4 or sell for $7 each
10*$7=$70