Mark M. answered 10/12/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
x = 3t + 2 and y = 2t + 3
Since x = 3t + 2, t = (x - 2) /3
So, y = 2[(x-2) / 3] + 3
y = (2/3)x + (5/3)
This is a line with slope 2/3 and y-intercept (0, 5/3).