Mark M. answered 10/09/19
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
y = √(x-1) / (x8 + 2)
lny = ln [√(x-1) / (x8 + 2) ]
lny = (1/2)ln(x-1) - ln(x8 +2)
y' / y = 1 / (2(x-1) - 8x7 / (x8 + 2)
y' = y[ 1/(2x-2) - 8x7/ (x8 +2) ]
y' = √(x-1) / (x8 + 2) [ 1/(2x-2) - 8x7 / (x8+2) ]