The zeroes can be written as
(x-2)(x+2) = x2-4
Divide the function by x2-4 using Polynomial Long Division
You should get x2+x-30
Then factor that into (x+6)(x-5)
Set each equal to zero so the other zeroes are -6 and 5
Shubham K.
asked 09/30/19The zeroes can be written as
(x-2)(x+2) = x2-4
Divide the function by x2-4 using Polynomial Long Division
You should get x2+x-30
Then factor that into (x+6)(x-5)
Set each equal to zero so the other zeroes are -6 and 5
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