Let equation 1 be y = -x + 1
Let equation 2 be y = -x - 1 the 2 lines are parallel
Choose a point on equation 1 , one point would be (1,0)
The perpendicular line originating from equation 1 at the point (1,0) would be yp = x - 1
Now let's see where this line intersects with equation 2 which would be the shortest distance
if x - 1 = -x -1 then 2x = 0 or x = 0 on equation 2. That point would be (0,-1)
The distance between these 2 points is sqrt{ (1-0)2 + (0+1)2) = sqrt(2) = 1.4 (to the nearest tenth)