find a liner function h given h(1)=4 and h(-2)=13. then find h(2)

Question

find a liner function h given h(1)=4 and h(-2)=13. then find h(2)

Answer 1

Leslie,

 

h(1) = 4

So one point of the function is (1,4)

 

h(-2) = 13

Second point of the function is (-2, 13)

 

the linear function h(x) is given as h(x) = mx + c, where m is the slope and c is the y intercept.

 

Slope = (y2-y1)/(x2-x1) = (13-4)/(-2-1)) = -3

 

so h(x)  -3(x) + c

 

Substitute for values using point 1

4 = (-3)*(1) + c

c = 7

 

Hence h(x) = -3*x + 7

 

h(2) = -3*2 + 7 = 1