Mark M. answered 09/12/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f'(a) = limx→a[(f(x) - f(a)) / (x - a)]
So, limx→2 [(f(x) - f(2)) / (x - 2] = f'(2) = 0
Answer: C
John S.
asked 09/12/19If f is a function such that lim x->2 (f(x) - f(2))/(x-2) = 0, which of the following must be true?
(A) The limit of f(x) as x approaches 2 does not exist.
(B) f is not defined at x = 2;
(C) The derivative of f at x = 2 is 0.
(D) f is continuous at x = 0;
(E) f(2) = 0
I can't figure this one out, Thanks.
Mark M. answered 09/12/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f'(a) = limx→a[(f(x) - f(a)) / (x - a)]
So, limx→2 [(f(x) - f(2)) / (x - 2] = f'(2) = 0
Answer: C
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