Winston T.
asked 09/11/19Find the points on the given curve where the tangent line is horizontal or vertical
Assume (0≤θ≤2π). Enter your answers as a comma-separated list of ordered pairs.)
r=e^(θ)
| horizontal tangent | (r, θ) = | |||
| vertical tangent | (r, θ) = |
Apparently I keep getting this answer wrong.
1 Expert Answer
Doug C. answered 09/11/19
Math Tutor with Reputation to make difficult concepts understandable
Here us a suggestion.
Since y = rsinθ, y = eθsinθ. Similarly, x=eθcosθ.
Find dy/dθ and dx/dθ. Then dy/dx = dy/dθ / dx/dθ.
Horizontal tangent lines when dy/dx = 0. Vertical tangent lines when dy/dx is undefined.
I get answers like this: Vertical: (eπ/4, π/4), (e5pi/4, 5π/4).
Horizontal: (e3π/4,3π/4), (e7π/4, 7π/4).
If those answers appear to match what you are looking for and you need additional clarification, let me know--perhaps I can create a video answer with more detail.
Winston T.
I'm still confused on how you got that answer, considering how the question asked just for 1 tangent specifically for each "(r,θ)" yet you have 2 for each. In my work, I tried having both horizontal dy/dx=0 => x+y=0 => θ =arctan(-1) =n(pi) - (pi)/4 where n is any integer. As 0≤θ≤2π, n=1,2 and for vertical tangent dy/dx=0 and dy/dx=0 => x+y=0 => θ =arctan(-1) =m(pi) - (pi)/4 where m is any integer. As 0≤θ≤2π, m=0,1. However this is consider wrong09/11/19
Doug C.
The question is what did you get for dy/dx (in terms of theta)? I got: dy/dx = (costheta + sintheta) / (cos theta - sin theta). In that case dy/dx = 0 when the numerator = 0, or when cos theta = -sin theta). That happens in the interval from 0 to 2pi when theta = 3pi/4 or 7pi/4. The vertical tangents happen when dy/dx has denominator = 0, or when costheta = sintheta. That happens at theta = pi/4 or 5pi/4. Are you entering answers is some online tool? If yes, did you try entering the answers I provided?09/11/19
Doug C.
Try attaching the following to the URL for the Desmos online graphing calculator: "calculator/05xnebgnob" (www.desmos.com/). You will see a graph of r = e^theta along with the points where vertical and horizontal tangents are located.09/11/19
Doug C.
Or: www.desmos.com/calculator/eufkkbrbld shows the tangent lines09/11/19
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Patrick B.
The derivative is never zero09/11/19