Find the slope m and an equation of the tangent line to the graph of the function f at the specified point.

Question

f(x)=x²/x+2 ; (3,9/5)

Answer 1

if the function is f(x) = x²/(x+2), the f'(x) = (3x²+4x)/(x+2)²

At the point in question, f'(3) = 21/25

So, the equation of the tangent line takes the form y-9/5 = 21/25(x-3) or

y = (21/25)x - 18/25