
Victoria V. answered 09/10/19
Math Teacher: 20 Yrs Teaching/Tutoring CALC 1, PRECALC, ALG 2, TRIG
Hi Dat B.
Parallel lines have the same slope. Since the line you need to be parallel to has a slope of (3/2) (the number multiplied to the "x"), then your line must also have a slope of (3/2).
Since it needs to pass through (-2,3), we need to write an equation of the form y = mx + b
where m is the slope (3/2) and b is where it crosses the y-axis, known as the "y-intercept".
Since we have a point where x = -2 and y = 3; and we have the slope, we can plug all of these into
the linear equation y=mx+b and solve for b.
y = m x + b
3 = (3/2)(-2) + b
3 = -3 + b
6 = b
Now we can write the equation, filling in just the m and the b and leaving x and y as x and y.
y = (3/2) x + 6
This is the equation of the line you are looking for.