Mark M. answered 09/06/19
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
P = (2, 1)
f(x) = x2 - 2x + 1
f'(x) = 2x - 2
f'(2) = 2
y = 2x + b
1 = 2(2) + b
1 = 4 + b
-3 = b
y = 2x - 3
Kalea R.
asked 09/05/19Find an equation for the tangent line at the point P (2,f(2)) on the graph of
f(x) = x^2 - 2x +1
Mark M. answered 09/06/19
Mathematics Teacher - NCLB Highly Qualified
P = (2, 1)
f(x) = x2 - 2x + 1
f'(x) = 2x - 2
f'(2) = 2
y = 2x + b
1 = 2(2) + b
1 = 4 + b
-3 = b
y = 2x - 3
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