Tom N. answered • 08/31/19
Tutor
4.9
(503)
Strong proficiency in elementary and advanced mathematics
Let u = x2 and so du = 2xdx so the integral ∫03 xf(x2)dx = (1/2)∫09 f(u)du =(1/2)(-10)= -5.
Tom N.
tutor
If you look at the step where u=x^2 then du =2xdx or xdx=du/2. The problem gives you the integrated value of f(x)dx form 0 to 9 as -10. This can also be written as integral of f(u)du from 0 to 9. And so the integral of xf(x^2)dx from 0 to 3 becomes -10 /2 or -5.
Report
01/12/24
Amy N.
Why did the range change when you substituted? From 0 to 3, to 0 to 9?01/12/24