How to find all possible values of b so g(x)=2x^2+bx+3 has x-intercepts

Answer 1

Here if you use the quadratic formula with

a = 2

b = b

c = 3

The roots of g(x) are at the x-intercepts: (x,0)

x = -b +/- square root of (b² - 4*2*3 )

2*2

x = -b + square root of (b² - 24)

4

x = -b - square root of (b² - 24)

4

That's really all you can do for solutions (x-intercepts).