The smallest number of shots by a shooter to ensure a probability of more than 0.95 of hitting the bulls eye at least twice?

Question

The probability of a target shooter hitting the bulls eye on any one shot is 0.2, what is the The smallest number of shots by the shooter to ensure a probability of more than 0.95 of hitting the bulls eye at least twice?

any help is welcome!!!

you guys have no idea how much I appreciate your help

Answer 1

(0.2)* x > 0.95

x > 0.95 / 0.2

x > 4.75 shots

5 shots is the minumum number of shots to give a probability > 0.95.

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