
Jayson K. answered 08/26/19
Math homework help
Okay, so you are given that:
lim f(x) = 8 & lim g(x) = 3
x→1 x→1
Thus,
lim 3√(f(x)g(x) + 3)
x→1
= 3√(lim ( f(x)g(x) + 3)
x→1
= 3√ (lim f(x)g(x) + lim 3)
x→1 x→1
*= 3√( 8*3 + 3)
= 3√ 27 = 3
*NOTE: lim 3 = 3 since it's just a constant. No matter what number you approach, your y - value always
x→1
wants to go to 3.
In other words: lim c = c (regardless of what number x is approaching)
x→a
Hope this helps.
Mr. K
Cass G.
Explaining about the constant helped a lot, I completely forgot about that Thank you so much!! :D08/26/19