Calculate the Integral: ∫ sin(sin(2x+1))dx

Question

Calculate the Integral: ∫ sin(sin(2x+1))dx

Answer 1

where J refers to the Bessel function. So if you let u = 2x+1, then du = 2dx and (1/2)du = dx

you could then express the integral of sin{ sin(2x+1) }dx as (1/2)sin{ sin(u) }du

use the answer above in terms of u and then make the final substitution back to a function of x.