Mark M. answered 08/23/19
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = cosx
f'(x) = -sinx
f"(x) = -cosx
f'''(x) = sinx
f(4)(x) = cosx
f(4)(x) = f(8)(x) = f(12)(x) = .... f(24)(x) = ...
So, f(25)(x) = [f(24)(x)]' = (cosx)' = -sinx