Find the inverse

Question

Y=1+In(-x) the domain range and the asymptote

Answer 1

y = 1 + ln(-x) → Domain: -x>0 or x<0; Range: y all real numbers

Exchange x and y → x = 1 + ln(-y) → Solve for y

ln(-y) = x - 1 → -y = e^x-1 = e^x/e

So y = -e^x/e Or if f(x) = 1 + ln(-x), then f^-1(x) = -e^x/e

Domain: x all real numbers Range: y<0;