
Mark M. answered 08/16/19
Mathematics Teacher - NCLB Highly Qualified
f(0) = 0
f(1) = 5
f(n) = f(n-1) + (2n - 1)5
Leticia C.
asked 08/16/19Quadratic Pattern
1st Difference. 2nd difference
F(0)=0.
> +5.
>+10
f(1)=⁵
>+15
f(2)=²⁰ >+10
>+25
f(3)=45
Mark M. answered 08/16/19
Mathematics Teacher - NCLB Highly Qualified
f(0) = 0
f(1) = 5
f(n) = f(n-1) + (2n - 1)5
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