A rectangle has an area of 40 square units. The length is 6 units greater than the width. What are the dimensions of the rectangle?

Answer 1

Area, A = 40 sq. units

Width = W

Length, L = 6+W

Area, A = L*W

A = (6+W)*W = 6W + W^2 = 40

W^2 + 6W - 40 = 0

Solve for W:

W = 4 or -10

W = 4 since you cannot have a negative value.

L = W+6 = 4+6 = 10

Hope this helps!