Mark M. answered 08/01/19
Retired college math professor. Extensive tutoring experience.
logaC - logax = 5/3
loga(C/x) = 5/3
C/x = a5/3
C = x(a5/3)
So, x = C / a5/3 (or Ca-5/3)
Mark M. answered 08/01/19
Retired college math professor. Extensive tutoring experience.
logaC - logax = 5/3
loga(C/x) = 5/3
C/x = a5/3
C = x(a5/3)
So, x = C / a5/3 (or Ca-5/3)
Sam Z. answered 07/31/19
Math/Science Tutor
("a"^?=C)-("a"^?=x)=5/3
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