Derivatives-Trigonometric: Question is in the description

Question

Find the equation of the tangent line to the curve y = 5 sec ( x ) − 10 cos ( x ) at the point ( π / 3 , 5 ) . Write your answer in the form y = mx + b where m is the slope and b is the y -intercept

Answer 1

y = 5secx - 10cosx

y' = 5secxtanx + 10sinx

Slope of tangent line = 5(2)(√3) + 10(√3/2) = 15√3

Equation of tangent line: y - 5 = 15√3(x - π/3)

y = (15√3)x + 5(1-π√3)