To solve this problem, you will need to begin by taking your given equation and solving for y to put it into slope-intercept form, y=mx+b. This will give you the equation, y=-x+2. This tells you that your line has a slope of -1 and a y-intercept of 2. If you want the line perpendicular to the given line, you must the slope that is the negative reciprocal of the given slope. This would give you a slope of positive one.
Now, you need to use the given point and your new slope in the point-slope equation, y-y1=m(x-x1). Plugging in your values gives you the following: y-9=1(x-(-4)). Using distribution and simplification, you get the new equation y=x+13.
