Find an equation of a circle that satisfies the given conditions. Center at the origin, passes through (7, 8)

Question

Find an equation of a circle that satisfies the given conditions.

Center at the origin, passes through (7, 8)

Answer 1

radius =sqrt (7^2 + 8^2) = sqrt( (113)

equation: (x-0)^2+ (y-0)^2 =sqrt(113)^2

or x^2 + y^2 = 113