Integral Question

Question

Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = In(x), y = 2, x = 1 is revolved around the line y = -2.

Answer 1

The integral becomes π∫₁^{e^2}[(2-(-2))²- ( Lnx -(-2))²]dx which equals π∫₁^{e^2}[4² -(lnx +2)²]dx.