
Patrick B. answered 06/19/19
Math and computer tutor/teacher
2y < 15 - 3x
y < (-3/2)x + 15/2
intercept point at (0,15/2)
go down three and 2 to the right...
DASHED LINE, crosses the x-axis at (5,0)
Testing (0,0): 3(0) + 2(0) > 15
0 + 0 > 15
0 > 15 FALSE
shades AWAY form the origin
7x - 4y > 9
7x - 9 - 4y > 0
7x - 9 > 4y
(7/4)x - 9/4 > y
intercept point at (0, -9/4)
Go up 7 and 4 to the right
DASHED LINE, crosses the x-axis at (9/7,0)
Tests (0,0): 7(0) - 4(0) > 9
0 - 0 > 9
0 > 9 FALSE
shades away from the origin
Now for the intersection point:
3x+2y = 15
7x - 4y = 9
Multiplies top equation by 2, and then adds them together
6x + 4y = 30
7x - 4y = 9
13x = 39
x = 3
3(3) + 2y = 15
9 + 2y = 15
2y = 6
y = 3
check: 7(3) - 4(3) = 21 - 12 = 9
intersection is at (3,3)
So the solution are where the two regions overlap.
The triangular portion of the solution crosses (1.286, 0), (3,3), and (5,0)
picture located in the RESOUCES section under toolkit, names TWO INEQUALITIES.jpg