hi i need some help

Question

given that f(X) = ax+b and f(2)=13 and f^-1 (3) =0 find a and b

Answer 1

f(x)= ax +b so f(2)= 2a +b +13 to find f^-1(x) solve for x and switch positions that is f(x)-b = ax and solving for x gives ( f(x) - b)/a =x so f^-1(x) = (x - b)/a using the info given f^-1(3) = 0 = (3 - b)/a giving b=3 solving for a gives

13 -3 = 2a and a = 5.