The method is to separate variables. The expression x3 + (1/y)dy/dx = 0
is -x3 = (1/y)dy/dx or -x3 dx = (1/y) dy
Integrating, you obtain ln(y) = -(1/4)x4 + C or y = Ke(-x4/4)
Where C & K are constants.
Bob D.
asked 06/14/19Hi! I was wondering how you would antidifferentiate this: x^3+(1/y)(dy/dx)
The method is to separate variables. The expression x3 + (1/y)dy/dx = 0
is -x3 = (1/y)dy/dx or -x3 dx = (1/y) dy
Integrating, you obtain ln(y) = -(1/4)x4 + C or y = Ke(-x4/4)
Where C & K are constants.
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