Calculus slope of a line normal to the curve HELP PLEASE
Find the slope of the line normal to the curve y = 3x2-23x + 5 at x = 5
2 Answers By Expert Tutors
y = 3 * x^2 - 23 * x + 5
We get the derivative as
dy/dx = 6 * x - 23
At x = 5 the slope is 7. The slope of the normal line is the negative reciprocal of the slope of the line so
Normal line slope = - 1 / 7
First you take the derivative of y which is 6x-23. Then you plug in 5 to x and you will get 7. The slope of a line normal is 7
Ask your own question and get expert help fast and free!
Ask a question for free
No subscriptions or upfront payments, just fast, free answers.