Tom N. answered 06/12/19
Strong proficiency in elementary and advanced mathematics
V= 2π∫01.15xe-x^2dx = -10π∫01.1du/2 where u= e-x^2 and du =- 2xe-x^2dx so V = -5πe-x^2|01.1 and
V= -5π(e-1.21 -1) V= 5π(1-1/e1.21).
Katie M.
asked 06/12/19y=5e^(-x)^2, y=0, x=0, x=1.1
The circumference of a typical shell= 2pix
The height of this shell= 5e^(-x^2)
Thus the volume V= ?
and dx= ?
I figured out the answers to the first two, but now I'm stuck. What would the answers be to the last two?
Tom N. answered 06/12/19
Strong proficiency in elementary and advanced mathematics
V= 2π∫01.15xe-x^2dx = -10π∫01.1du/2 where u= e-x^2 and du =- 2xe-x^2dx so V = -5πe-x^2|01.1 and
V= -5π(e-1.21 -1) V= 5π(1-1/e1.21).
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