Tom N. answered 06/08/19
Strong proficiency in elementary and advanced mathematics
Prpfit = revenue -cost so profit = 70q - q2/2 -( 13q +500) = 51q-q2/2 -500 to find the maximum profit take the derivative of the profit function wrt q or dP/dq =51 - q and to maximize set this to 0 so 51-q = 0 or q=51. Now go back to the profit equation and put the maximum value in to find the maximum profit. This gives 512- 512/2 -500 which equals 512/2 -500 and P = $800.50