I agree with Patrick B, but perhaps there is an easier way to see it
H(u)=(u-√u)(u+√u)=u2 - u
(The sum of 2 numbers times the difference of the same 2 numbers = the difference of "their" squares.)
Then the derivative is obvious!
Jo J.
asked 06/03/19can you explain each step like how you got (u^2-u)
Can you explain it by using the product rule .
Thanks !
I agree with Patrick B, but perhaps there is an easier way to see it
H(u)=(u-√u)(u+√u)=u2 - u
(The sum of 2 numbers times the difference of the same 2 numbers = the difference of "their" squares.)
Then the derivative is obvious!
Patrick B. answered 06/05/19
Math and computer tutor/teacher
H = (u - u^(1/2)) ( u + u^(1/2))
dH/du = (u - u^(1/2))* (1 + (1/2)u^(-1/2)) + ( u + u^(1/2))(1 - (1/2)u^(-1/2)) <--- product rule
= u - u^(1/2) + (1/2)u^(-1/2)( u - u^(1/2) ) + (u + u^(1/2) - (1/2)u^(-1/2)(u + u^(1/2))
= u - u^(1/2) + (1/2)u^(1/2) - 1/2 + u + u^(1/2) - 1/2 u^(1/2)- 1/2
= 2u -1 ;
Now to check: if we FOIL it first: H = u^2 - u
so then dH/du = 2u - 1
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