Jon P. answered 01/06/15
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Since the x values are separated by 1, it's easy to use the method of taking differences to figure this out.
First take the differences between the successive values of f(x):
3 - 12 = -9
0 - 3 = -3
3 - 0 = 3
12 - 3 = 9
27 - 12 = 15
If the difference between each value of f(x) was the same for every x, then the equation would be a first degree polynomial, or a linear function.
So now take the differences of the first set of differences:
(-3) - (-9) = 6
3 - (-3) = 6
9 - 3 = 6
15 = 9 = 6
Since the second set of differences are the same, that means that the function is a second degree polynomial, which is quadratic.
In other words, the number of differences you have to take until you get a constant series is equal to the degree of the polynomial.
HOWEVER:
- If the increments between the values of x were not all 1, then this would NOT work. You would need an adjustment to the procedure.
- Not all functions are polynomials. You will only reach a constant set of differences for a polynomial equation.
Play around with this. Make up polynomial equations of different degrees and make tables of values using successive values of x. You'll see how it works!
Jon