The lenth of a rectanglular table is less than twice it's width. If the perimeter is 70 inches, find the dimensions of the table

Answer 1

Suppose the length is exactly 2 times the width.

The perimeter is 2W + 2L = 70

But L = 2W, so we can substitute L for the 2W:

L + 2L = 70

3L = 70, and L = 70/3

And W = L/2 = 35/3

Now, what happens when L gets smaller? Using the first equation, a smaller L simply means that W is larger---this continues for all values of L down to 0. There is no unique answer---perhaps there is an error in how the problem is stated?