Sarah F.
asked 12/22/14the width of a rectangle is 2 inches less than its length, and the area is 35 square inches. what is the length and width?
I need help with this word problem. It's crunch time.
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4 Answers By Expert Tutors
Hi Sarah,
Ok
let Length = x
then width = x -2 (2 inches less than length
now
A = Lw
35 = x (x -2)
35 = x2 - 2x
x2 -2x -35 = 0
(x-7)(x+5) = 0
x-7=0
x=7 (we won't use the other factor since it would give us a negative length
so length = 7
width = 7 -2 = 5
Hope this helps

Moise D. answered 12/22/14
Tutor
New to Wyzant
Patient and Courageous Tutor in Math and Related Subjects
Hi,
Here you have to make sure you interpret the problem correctly.
There is Width and Length of a rectangle, and the width is 2 inches less than the length of a rectangle. This implies that you can assign an unknown letter, X, to be the length and hence the width will be (X-2) which is exactly what's stated in the problem..
Using the formula for the area of rectangle, Area= (width)*(length), in this case Area = (X-2)*(X), since its area is given and it is 35 square inches, helps you to find the unknown
This leads you to solving the equation (X-2)(X)=35 => X2-2X-35=0... This is a quadratic expression that may have to real values, after solving, keep the one that makes sense.
Antoinette W. answered 12/22/14
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Caring, Effective Tutor- Math, Reading, Test Prep, Sports Conditioning
length = l
width = "width is" means w = "2 inches less" means subtract 2 "than" [switch first and last] "its length" means l= l - 2
Area = 35 in 2
Area of a rectangle = (l)(w)
Substitute
A = (l)(l-2)
35 = (l)(l-2)
Distribute/Multiply
35 = l2 - 2l
Balance
l2 - 2l - 35 = 0
Factor
(l - 7)(l + 5) = 0
Solve (set each factor = to 0)
This will lead you to find the length
Re-read question to find the phrase that will help you find the width
width = "width is" means w = "2 inches less" means subtract 2 "than" [switch first and last] "its length" means l= l - 2
Area = 35 in 2
Area of a rectangle = (l)(w)
Substitute
A = (l)(l-2)
35 = (l)(l-2)
Distribute/Multiply
35 = l2 - 2l
Balance
l2 - 2l - 35 = 0
Factor
(l - 7)(l + 5) = 0
Solve (set each factor = to 0)
This will lead you to find the length
Re-read question to find the phrase that will help you find the width
Let X = the length; then the width = X - 2
the Area of a rectangle = L x W = X(X - 2)
since the area = 35cm2, we write 35cm2 = X(X - 2)
expanding this equation, 35cm2 = X2 - 2X
rewriting, 0 = X2 - 2X -35cm2
factoring, 0 = (X - 5cm)(X + 7cm)
so the two roots are -5 and +7, but since no length can equal a minus number, we can discard that root
which leaves us with +7cm, thus X - 2 = +5cm
so, the length = +7cm, and the width = +5cm
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