A car drives down a road in such a way that its velocity ( in m/s) at time t (seconds) is v(t)=3t^(1/2)+3. Then the car's average velocity (in m/s) between t=4 and t=6 is equal to

Answer 1

First, integrate the expression for speed---this gives you distance as a function of time. Evaluate this for the two given times and you have the distance travelled. Finally, divide this by 2 to the get the average velocity.

Average velocity between any two points is the distance divided by the time

Answer 2

(1/2s) * ∫v(t) dt, with the integral taken from t=4 to t=6.