Tom N. answered 05/24/19
Strong proficiency in elementary and advanced mathematics
Make a force diagram of the block on the ramp at 60° and find the component of mg parallel to the ramp which in this case is mgsin60°. The work done is W= F•s where s is the distance traveled down the ramp. Using this expression then W = 10400J = mgsin60°42kgm2/sec2 m= 10400/9.8•42•√3/2 Doing the math m=29.177kg.