HI. Assuming there are 10 soccer matches being played with 3 options. ( Win/ draw/ loose). How many possible combinations can i have?

Answer 1

Answer: 3^10= 59,049

Solution:

Let’s just look at two games to understand the concept.

Game one in first column and Game two in second column.

Assumes the outcome of one game is independent of the outcome of any other game.

Make a sample space which is like a decision tree:

ww

wd

wl

dw

dd

dl

lw

ld

ll

You can see that there are two games and you can see that there are three outcomes per game. You can see there are nine unique outcomes or arrangements. That comes from The number that comes to the number of games power which, in this case, is 3^2=9 outcomes.